If one root of x^-px+q=0 is twice the other show that 2p^=9q
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2
use sum and product of roots formulas only
sum of roots =-b/a
product of roots =c/a
sum of roots =-b/a
product of roots =c/a
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Thank you for asking this question.
Here is your answer:
et ß is one root
and 2ß is 2nd root
x² -px + q = 0
so,
sum of roots = P
ß + 2ß = P
ß = P/3 ---(1)
product of roots = q
2ß.ß = q
2ß² = q
put eqn (1)
2(P/3)² = q
2P² = 9q
If there is any confusion please leave a comment below.
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