Question

If one root of yhe equation 2x^2 -10x+k=0 is the reciprocal of the other the value of k is

Answer 1

Answer:

k=-2x^2+10x

Step-by-step explanation: 2x^-10x+k=0

                                            2x^2+k=10x(-2x^2)=0+(-2x^2)

                                            k-10x=-2x^2

                                            k-10x+10x=-2x^2+10x

                                            k=-2x^2+10x

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