If one root the equation 2x² + kx + 4 = 0 is 2, then the other root is
(a)6
(b)−6
(c)−1
(d)1
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62
SOLUTION :
Option (d) is correct : 1
Let α be the one root of the equation and β be the other root .
Given : 2x² + kx + 4 = 0 , α = 2
On comparing the given equation with ax² + bx + c = 0
Here, a = 2 , b = k , c = 4
Product of zeroes = c/a
α × β = c/a
2 × β = 4/2
2β = 2
β = 2/2
β = 1
Hence, the other root of the equation is β = 1.
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If one root the equation 2x² + kx + 4 = 0 is 2, then the other root is
(a)6
(b)−6
(c)−1
(d)1√√√
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