Math, asked by Abrar11, 1 year ago

if one-seventh of a number exceeds its its eleventh part by 100 , then the number is:

Answers

Answered by gffxvgj
33
Let the number be 'x'
1/7×x-x/11=100
x/7-x/11=100
(11x-7x)/77=100
4x/77=100
x=100×77/4
x=25×77
x=1925
Answered by boffeemadrid
25

Answer:

The number is =1925

Step-by-step explanation:

Let the number be =x , then according to the question, one-seventh of a number exceeds its its eleventh part by 100 that is

\frac{x}{7}-\frac{x}{11}=100

\frac{11x-7x}{77}=100

4x=7700

x=\frac{7700}{4}

x=1925

Thus, the number is =1925.

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