Question

If one side of a rectangle is three less than the other side and the perimeter is 46 inches, find the area of the rectangle.

Answer 1

let tepwo adjusant side be x and y

given condition,

y=x-3

we know perimeter of rectangle=2 (x+y)

=2 (x+x-3)

46=4x-6

52÷4=x

13=x

y=11

now area of rectangle is given as, (x×y)

(13×11)

143