if one side of a square is decreased by 2m and the other is increased by 1 m a rectangle will be formed whose area is 9 square M less than the area of the square find the sides of the square
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Let the side of the square be x m
By question,
Area of rectangle + 9 = Area of square
Length of rectangle = x - 2
Breadth of rectangle = x - 1
Area = l*b
Area of square = x^2
Now,
l*b + 9 = x^2
(x-2)(x-1) + 9 = x^2
x^2 - x - 2x + 2 + 9 = x^2
-3x = -2-9
-3x = -11
x = 11/3m
Thus, side of the square is 11/3m
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Answer:
Step-by-step explanation:
Answer is in photo 7 m
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