Question

if one side of a square is increased by 2 m and other side is reduced by 2 metres , a rectangle is formed whose perimeter is 48m. find the side of the original square

Answer 1

perimeter of rectangle =2*(l+b)
48 =2*(2+b)
48/2 =(2+b)
24 =(2+b)
24-2 =b
22 =b
area of original square= side *side
=22*22
=484

Answer 2

2(l+b)= 48
Let x= length of the square
l=x+2
b=x-2
Hence,
2(x+2+x-2)=48
2(2x)=48
4x=48
x=12
So that the side of the original square is 12 metres.