thedifference of two number is 3 and the difference if their square is 27 find the numbers
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let the no.be a and b
according to question
a-b=3 mark as 1st equation
and a^2-b^2=27
use a^2-b^2=(a-b)(a+b)
(a-b)(a+b)=27
3(a+b)=27
(a+b)=27/3=9. mark as 2nd equation
add 1st and 2nd equation, we get
2a=12
a=6
put value of a in 1st equation, we get
b=9
according to question
a-b=3 mark as 1st equation
and a^2-b^2=27
use a^2-b^2=(a-b)(a+b)
(a-b)(a+b)=27
3(a+b)=27
(a+b)=27/3=9. mark as 2nd equation
add 1st and 2nd equation, we get
2a=12
a=6
put value of a in 1st equation, we get
b=9
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