If one side of square increased by 2metres and other side reduced by 2metres, rectangle is formed whose perimeter 48m. Find side of original square
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let one side of square is x the the sides of rectangle are x-2 and x+2.
2[(x-2) +(x+2)] = 48
2(2x) = 48
x=12
therefore actual side of square is 12m.
2[(x-2) +(x+2)] = 48
2(2x) = 48
x=12
therefore actual side of square is 12m.
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