Question

if one solution of quadratic equation kx ^2 + 3 x - 4 = 0 if x = 2 then K =
a) 1÷2
b) -1÷2
c) 2
d) -2

Answer 1

a) is right answer ......

Answer 2

$k{x}^{2} + 3x - 4 = 0$
putting x=2
$4k + 6 - 4 = 0$
$4k + 2 = 0$
$4k = - 2$
$k = \frac{ - 1}{2}$
HOPE IT HELPS