If one solution of the equation 3x^2=8x+2k+1 is 7 times the other.find the value of k.
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rearrange the equation
3x^2 -8x - (2k +1) =0
let one root be p
then second root will be seven time = 7p
sum of root = -b/a
p+ 7p = -(-8)/3
8p = 8/3
p =1/3
product of root = c/a
7p × p = -(2k +1)/3
7(1/3)^2 = -(2k +1)/3
7/9=-(2k+1)/3
7= -3(2k+1)
7= -6k -3
10= -6k
k = -5/3
3x^2 -8x - (2k +1) =0
let one root be p
then second root will be seven time = 7p
sum of root = -b/a
p+ 7p = -(-8)/3
8p = 8/3
p =1/3
product of root = c/a
7p × p = -(2k +1)/3
7(1/3)^2 = -(2k +1)/3
7/9=-(2k+1)/3
7= -3(2k+1)
7= -6k -3
10= -6k
k = -5/3
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