Question

if one zero is 4 ,- 18 find the quadratic polynomial

Answer 1

Ans.
x^2-(4+-18)x-72.
Am I right dear?

Answer 2

Hi !

We know that,

${x}^{2} - ( \alpha + \beta )x + ( \alpha \beta )$

Putting the values of zeroes i.e. 4 and -18 we get,

${x}^{2} - (4 + ( - 18))x + (4 \times - 18) \\ \\ {x}^{2} - (4 - 18)x - 72 \\ \\ {x}^{2} - ( - 12)x - 72 \\ \\ {x}^{2} + 12x - 72$

Given is the required polynomial ^-^