If one zero of 2z^2- 3x+ k is the reciprocal of the other , find the value of k
Answers
Answered by
2
Hi ,
( plz , check the problem i think there is
a typing error . z instead of x )
Let p( x ) = 2x ^2 - 3x + k
compare this with ax^2 + bx + c we get
a = 2 ; b = -3 ; c = k
according to the problem ,
one zero is reciprocal to another,
let us assume
one zero = p
second zero = 1/p
product of the zeroes = c / a
p × 1/ p = k / 2
1 = k /2
2 = k
therefore ,
k = 2
i hope this will useful to you.
*****
( plz , check the problem i think there is
a typing error . z instead of x )
Let p( x ) = 2x ^2 - 3x + k
compare this with ax^2 + bx + c we get
a = 2 ; b = -3 ; c = k
according to the problem ,
one zero is reciprocal to another,
let us assume
one zero = p
second zero = 1/p
product of the zeroes = c / a
p × 1/ p = k / 2
1 = k /2
2 = k
therefore ,
k = 2
i hope this will useful to you.
*****
Answered by
1
Hello friend !!
I think there is a small error in your question !!
The actual polynomial should be
= 2x² - 3x + k
a = 2
b = -3
c = k
Given :-
one zero is reciprocal to another,
one zero = α
second zero = 1/α
product of the zeroes = c / a
α × 1/α = k / 2
1 = k/2
k = 2 × 1 = 2
k = 2
Hope this Helps You !!
I think there is a small error in your question !!
The actual polynomial should be
= 2x² - 3x + k
a = 2
b = -3
c = k
Given :-
one zero is reciprocal to another,
one zero = α
second zero = 1/α
product of the zeroes = c / a
α × 1/α = k / 2
1 = k/2
k = 2 × 1 = 2
k = 2
Hope this Helps You !!
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