Question

If one zero of 3x²+8x+k be the reciprocal of the other, then k = ?

Answer 1

$\huge \mathfrak{answer}$

$let \: one \: zero \: be \: x$

$so \: reciprocal \: of \: the \: zero \: is \: \frac{1}{x}$

$\small \: product \: of \: zero = cofficent \: of {x}^{2}$

$\therefore \: x \times \frac{1}{x} = \frac{k}{3}$

$1 = \frac{k}{3}$

$k = 3$

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Answer 2

Hii !!

Solution :-

let the one zero be x then ,

other zero 1/x Hence, we know that product of zero = constant term coefficient of x² since, x × 1/x = k/3 1 = k/3 k = 3 Answer ✔

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