Only for scholars please tell me answer of this question in easy way but Step-by-step
a rectangle has length 18 cm and breadth 8 cm if its length is changed by 2/3 times and played by 3 /2 then what is the change on its area?
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Answer:
Step-by-step explanation:
length=10cm
breadth=8cm
Perimeter=2(10+8)cm
=36cm
length=(10cm+x)
breadth=(8cm+x)
Perimeter=2(10+x+8+x)cm
=2(2x+18)cm
=4x+36cm
let 4x+36cm be equation 1
Given perimeter=2×36
=72cm
let 72 be equation 2
therefore,from equation 1 and equation 2 we get 4x+36=72
4x=72-36
x=36/4
x=9
therefore length of the new rectangle=10+9=19cm
breadth of the new rectangle= 8+9=17cm
Area of a rectangle=(l×b)
Area of the new rectangle=(19×17)cm^2
=323cm^2
Hope this is helpful
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monisharmarts:
Oh I'm extremely sorry bro
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