If one zero of a polynomial 2x3 + x2 - 7x - 6 is 2, find all other zeroes.
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Answered by
31
x-2 must be a faactor of
2x3 + x2 - 7x - 6
dividing
2x3 + x2 - 7x - 6 by x-2 we get
(x+1)(x+3/2)
hence other roots are -1 and -3/2
2x3 + x2 - 7x - 6
dividing
2x3 + x2 - 7x - 6 by x-2 we get
(x+1)(x+3/2)
hence other roots are -1 and -3/2
Answered by
21
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