if one zero of a polynomial 3 x square - 8 x + 2 K +1 is 7 times the other, find the value of k
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Let x and y be zeros of p(x) 3x^2-8x+2k+1
X=7y. Given
X+y=-b/a
8y=8/3
Y=1/3
Xy=C/a
7y^2=2k+1/3
7×1/9=2k+1/3. Putting value of y
7=6k+3
6k=4
K=2/3
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X=7y. Given
X+y=-b/a
8y=8/3
Y=1/3
Xy=C/a
7y^2=2k+1/3
7×1/9=2k+1/3. Putting value of y
7=6k+3
6k=4
K=2/3
Mark as brainiest
Answered by
7
This should be the answer.
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