Question

If one zero of a quadratic polynomial f(x) = x²- 8kx -9 is negative of the other ,
find k

Answer 1

let the zeroes be a and b
such that b=-a
and,
a+b=-(-8k)/1
a+(-a)=8k
0=8k
so,
k=0

Answer 2

Step-by-step explanation:

Answer :-

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.