Question

if one zero of a qudrqtic polynomial ax2 +Bx +c is n times the other then the condition is​

Answer 1

Answer:

nb^2= (n+1)^2ac

Step-by-step explanation:

let the roots be p and np

p+np= -b/a ---------(1)

p×np= c/a ---------(2)

from (1)

p= -b/(n+1)a

substitute of value in (2)

n×(-b/(n+1)a)^2= nb^2/(n+1)^2a^2= c/a

so, nb^2= (n+1)^2ac

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