Question

if one zero of p(x)= 2x^2-3x+p is 3 find the value of p and the other root.

Answer 1

Step-by-step explanation:

Ҳ+Ŷ=3/2

3+Ŷ=3/2

Ŷ=-3/2

ҲŶ=P/2

ĹÊŤ , Ҳ=3

P=2(3)(-3/2)=-9

Answer 2

Answer:

Value of p is -9, roots are 3 and -3/2

Step-by-step explanation:

Since 3 is a root, therefore

2(3)^2 - 3(3) + p = 0

Solving for p we get p as -9

Now the equation is

2x^2-3x-9

On putting these values in the quadratic formula, we get

$\frac{3±\sqrt{9+4(2)(-9)}}{4}$

On solving this we get the roots to be 3 and -3/2