Question

If one zero of p(X)=4x^2-(8k^2-40k) x-9 is negative of the other find values of k

Answer 1

Answer:

Can u please check the Q again

Bcoz I am unable to get the ans

Answer 2

Answer:5,0

Step-by-step explanation:

Since both roots are negative of each other so their sum would be zero. So -b/a = 0

Here, b = -(8k^2 - 40k) and a = 4

So, -(-(8k^2 - 40k))/4 = 0

Solving this we would get:-

2k^2 - 10k = 0

or 2k( k - 5 ) = 0

So k = 0

or k = 5