Question

If one zero of p (x)=4xsquare -(8k square-40k)x-9 is negative of the other then find the value of k

Answer 1

Hey



The given equation is :-


4x² - ( 8k ² - 40k )x - 9




Solution :-


Let one zero be y .


So , other zero = ( - y ) .


Now ,


sum of zeroes = - ( b ) / a



So ,


y + ( - y ) = - [ - ( 8k² - 40k ) ] / 4


=> 8k² - 40k = 0


=> 8k ( k - 5 ) = 0


Now ,


if 8k = 0


then k = 0.


And ,


if ( k - 5 ) = 0


then k = 5


thanks :)