If one zero of p(x)=x²-9x+k is double the other ,then find the value of k
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Let, p(x)=2x²-5x-(2k+1)--------(1)
Also let, α be one root of (1).
Then the other root will be 2α.
α+2α=-(-5)/2
or, 3α=5/2
or, α=5/6
Again, α×2α=-(2k+1)/2
or, 2α²=-(2k+1)/2
or, -(2k+1)/2=2×(5/6)²
or, -(2k+1)=4×25/36
or, -2k-1=25/9
or, -2k=25/9+1
or, -2k=34/9
or, k=-34/9×1/2
or, k=-17/9 Ans.
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