Question

if one zero of polynomial 5z2+13z-p is reciprocal of the other then find p

Answer 1

the value of P is -5 I hope it is helpful

Answer 2

Answer:

The value of p is -5

Step-by-step explanation:

Given that if one zero of polynomial $5z^2+13z-p$ is reciprocal of the other then we have to find the value of p.

$\text{Comparing }5z^2+13z-p\text{ with standard quadratic polynomial of form }ax^2+bx+c\text{ we get}$

a=5, b=13 and c=-p

$\text{Product of roots=}\alpha.\beta=\frac{c}{a}=\frac{-p}{5}$

since the zeroes are reciprocal to each other.

therefore their product must be 1

⇒ $\frac{-p}{5}=1$

⇒ $p=-5$

Hence, the value of p is -5