if one zero of polynomial(a2+25)+36x+100a is the reciprocal of the other ,finf the value of a
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let the roots be k and (1/k)
product of roots=k*(1/k)=1
from eqn... product of roots=100a/(a^2+25)
100a/(a^2+25)=
100a=a。^2 +25
a^2 -100A+25=0
solve this quadratic
product of roots=k*(1/k)=1
from eqn... product of roots=100a/(a^2+25)
100a/(a^2+25)=
100a=a。^2 +25
a^2 -100A+25=0
solve this quadratic
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