Question

If one zero of polynomial (a2+9) x3+13x+6a is reciprocal of the other. Find the value of zero

Answer 1

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Your question :






Answer:


If one of the zero is reciprocal of the other, 

let one of the zero be α

Then the other zero will be 1/α

Product of roots = c/a

⇒ α × 1/α = 6a/(a²+9)

⇒ 1 = 6a/(a²+9)

⇒ a² + 9 = 6a

⇒ a² - 6a + 9 = 0

⇒ a² - 3a - 3a + 9= 0

⇒ a(a-3) -3(a-3) = 0

⇒ (a-3)(a-3) = 0

⇒ (a-3)²= 0

⇒ a = 3


Hence the value of a is 3....



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