Question

If one zero of quadratic polynomial 4x² - 8kx - 9 as negative of the other find the value of k.​

Answer 1

Answer :-

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

∴ k = 0 .

Hence, it is solved.

Answer 2

GIVEN :

Quadratic Polynomial : 4x² - 8kx - 9

One zero of Quadratic Polynomial = m

Let other zero be -m

Sum of Zeroes = m + (-m) = 0

We know that,

Sum of zeroes of a polynomial using coefficients = -b/a

a = 4

b = -8k

= -(-8k)/4

8k/4 = 0

2k = 0

k = 0/2

k = 0

Therefore, the value of k is 0.