Question

What is the product of 3a + 5 and 2a2 + 4a – 2?

Answer 1

Step-by-step explanation:

2a^2+4a-2

* 3a+5

6a^3+12a^2-6a

10a^2+20a-10

6a^3+22a^2-14a-10

May this help u mate!!

Answer 2

Given,

(3a+5) and (2a² + 4a -2)

To find,

The product of (3a+5) and (2a² + 4a -2).

Solution,

The product of (3a+5) and (2a² + 4a -2) will be (6a³ + 22a² + 14a - 10).

We can easily solve this problem by following the given steps.

Now, we know that when a number is given before a bracket then it is multiplied with all the digits in the bracket.

According to the question,

(3a + 5) (2a² + 4a -2)

3a (2a² + 4a -2) + 5 (2a² + 4a -2)

6a³ + 12a² - 6a + 10a² + 20a - 10 ( multiplying 3a and 5 into the respective brackets)

6a³ + 22a² + 14a - 10 ( The numbers with the same variables can be added and subtracted. So, we have added 12a² and 10a² and subtracted 6a from 20a.)

Hence, the product of (3a+5) and (2a² + 4a -2) is (6a³ + 22a² + 14a - 10).