if one zero of quadratic polynomial x^2-x(2+2k) is -4.find the value of K.
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Answered by
35
as one zero of polynomial is -4 , so itcsatifies it
Now, put x=-4 in polynomial and equate it with zero
x²-(2+2k)x
(-4)²⁻(2+2k)(-4)=0
16+8-8k=0
8k=24
k=3
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Now, put x=-4 in polynomial and equate it with zero
x²-(2+2k)x
(-4)²⁻(2+2k)(-4)=0
16+8-8k=0
8k=24
k=3
MARK AS BRAINLIEST IF YOU GOT ANSWER
Answered by
23
one zero of the quadratic polynomial x²-x(2+2k) is -4 ....
Put X=-4
p(-4)= (-4)²-(-4)(2+2k) =0
16+4(2+2k)=0
16+8+8k=0
8k=-16-8
8k=-24
k=-24/8
k=-3
Put X=-4
p(-4)= (-4)²-(-4)(2+2k) =0
16+4(2+2k)=0
16+8+8k=0
8k=-16-8
8k=-24
k=-24/8
k=-3
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