Question

if one zero of quadratic polynomial "x square - 4 x + K" is '2' then find the value of k​

Answer 1

Answer:

$x {}^{2} - 4x + k = 0 \\ (2) {}^{2} - 4(2) + k = 0 \\ 4 - 8 + k = 0 \\ - 4 + k = 0$

$\huge{\mathcal{\boxed{\orange{k=4}}}}$