Question

If one zero of the polynomial 14x^2-42k^2x-9 is negative of the other, find the value of k?

Answer 1

Hey user here is your answer!!!!!

______________________________

◆One zero is negative of other so,

$\alpha = - \beta$
◆Alpha + beta =-b/a

◆-Beta+beta=-(-42k)/14

◆0=42k/14

◆42k=0

◆k=0

So the value of k is 0

____________________________

⭐️ HOPE IT HELPS YOU⭐️

✌️Rohan ( Maths aryabhatta) ✌️

Answer 2

a=14 b=42k^2 c=9

Alpha=-Beta -Equation 1

Alpha+Beta = -b/a

From 1

-Beta+Beta=-(42k^2)/14

0=3k^2

0=k^2

k=0

Please mark it as brainliest answer