If one zero of the polynomial 2x 2 + 3x+gama is 1/2, find the value of gama and the other zero
Answers
Answered by
8
Let me use "r" instead of "gamma"
Let another root be s.
Then, we get
2x² + 3x + r = (2x - 1) (x- s)
This leads to
2x² + 3x + r = 2x² - (2s + 1)x + s
So, 2s + 1 = 3 and r = s
This gives us s = r = 1
Therefore, value of gamma is 1 and another root is 1 also.
Similar questions