Question

if one zero of the polynomial 2x^+3x+k is 1/2 find the value of k and other zero

Answer 1

P(x)=2x^2+3x+k
If , 1/2 is one of the zero
So,P(1/2)=2×(1/2)^2+3(1/2)+k
2×1/4+3/2+k=0
1/2+3/2+k=0
4/2+k=0
2+k=0
K=-2 Let the given zero (1/2) be alpha and another zero be beta Therefore, Alpha+beta=-b/a; 1/2+beta=-3/2; Beta=-3/2-1/2; Beta= -4/2; Beta=-2; Ans: k=-2 and another zero =-2

Answer 2

Hi friend,

p(x) = 2x²+3x+k

One zero is ½

p(½) = 2(½)² + 3(½) + k = 0

2(¼) + 3/2 + k = 0

½+3/2 + k = 0

k + 4/2 = 0

k+2 = 0

k = -2

Therefore, given polynomial is 2x²+3x-2

Finding another zero:-

Let another zero be x

Sum of zeroes = -3/2

½ + x = -3/2

x = -3/2-½

x = -4/2

x = -2

(OR)

Product of zeroes = -2/2

x(½) = -1

x/2 = -1

x = -1×2

x = -2

Therefore, another zero = -2

Hope it helps..