Question

If one zero of the polynomial 3x2–8x -(2k +1) is seven times the other, find the zeroes of the polynomial and the value of k.

Answer 1

Answer:

k = -5/3

Step-by-step explanation:

3x2 - 8x -(2k +1)

Let the zeroes be a and 7a.

So, sum of roots = 8a = 8/3

So, a = 1/3.

product of roots = 7a^2

                           = 7*1/9 = 7/9

So, -(2k+1)/3 = 7/9

6k + 3 = -7

6k = -10

k = -5/3

Hope it helps!!!!