If one zero of the polynomial 5z^2 + 13z _ p is reciprocal of the other then find p
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Answered by
3
5z2+13z-p
here
a=5
b=13
c=-p
since the zeroes are reciprocal to each other.
therefore their product must be1 .
=> c/a = 1
=> -p/a = 1
=> -p = 5
=> p= -5
therefore the value of p is -5
HOPE IT HELPS :)
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Answered by
1
Answer:
in given equation a =5 b=13 and c= - p
Let the one zero be a
and it's reciprocal means other zero 1/a
product of zeroes means a×(1/a)= c/ a
1= -p/5
5= -p
or p= -5
....hope it helps you....
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