Question

If one zero of the polynomial 5z^2 + 13z _ p is reciprocal of the other then find p​

Answer 1

5z2+13z-p 

here 

a=5

b=13

c=-p

since the zeroes are reciprocal to each other.

therefore their product must be1 .

=> c/a = 1

=> -p/a = 1

=> -p = 5

=> p= -5

therefore the value of p is -5

Answer 2

Answer:

here u goo

Explanation:

5z^2 + 13z - p = 0

Let the zeroes be alpha and 1/ alpha

Product of zeroes = c/a

Alpha x 1/alpha = -p/5

-p/5 = 1

p = -5