Question

If one zero of the polynomial 5z2 + 13z – p is reciprocal of the other, then find p​

Answer 1

Answer:

HII MATE....

HOPE ATTACHMENT WILL HELP YOU....

The value of P is -5 I hope it is helpful

Answer 2

Given :-

• one zero of the polynomial 5z² + 13z – p is reciprocal of the other .. Find P ?

Concept Used :-

The sum of the roots of the Equation ax² + bx + c = 0 , is given by = (-b/a)

and ,

→ Product of roots of the Equation is given by = c/a.

Solution :-

Put The Equation to Zero First..

→ 5z² + 13z – p = 0

Comparing with ax² + bx + c = 0, now, we get,

→ a = 5

→ b = 13

→ c = (-p)

Now, Let Roots of The Equation are ɑ and β...

Since, Roots are reciprocal of the other,

So,

→ ɑ = 1/ β

or,

→ β = 1/ɑ

Now, we know That,

→ Product of Roots are = c/a

→ ɑ * β = (-p)/5

→ ɑ * 1/ɑ = -p/5

→ 1 = -p/5

→ -p = 5

→ p = (-5) (Ans).

Hence, Value of p will be (-5).