Physics, asked by roopal4409, 11 months ago

The intensity of gamma radiation from a given source is I₀. On passing through 37.5 mm of lead it is reduced to I₀/8. The thickness of lead which will reduce it to I₀/2 is(a) (37.5)^{1/3}\ mm(b) (37.5)^{1/4}\ mm(c) \frac{37.5}{3}\ mm(d) (\frac{37.5}{4})\ mm

Answers

Answered by smartyrathore
2

here is your answer-

option(B)

❤️I hope it's help

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