Question

  If one zero of the polynomial 5z2 + 13z – p is reciprocal of the other, then find p. answer this I will mark as brainliest​

Answer 1

Step-by-step explanation:

${5z}^{2} + 13z - p = 0$

now a=5 b=13 and c=-p

$now$

$\alpha . \beta = \frac{c}{a}$

$\alpha . \beta = \frac{-p}{5}$

there fore the reciprocal of each other

there fore the product must be one

$\frac{ - p}{5} = 1$

p=-5