If one zero of the polynomial (a^2+9)x^2+13x+6a is reciprocal of other ,find the value of a
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p(x)=(a^2+9)x^2+13x+6a
let one of the zero of the polynomial p(x) be m then another be 1/m
now
products of zeroes =c/a
m×1/m=6a/a^2+9
1=6a/a^2+9
a^2+9=6a
a^2-6a=-9
a (a-6)=-9
a=-3 or 0
hope!it help you..
let one of the zero of the polynomial p(x) be m then another be 1/m
now
products of zeroes =c/a
m×1/m=6a/a^2+9
1=6a/a^2+9
a^2+9=6a
a^2-6a=-9
a (a-6)=-9
a=-3 or 0
hope!it help you..
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