Question

If one zero of the polynomial (a2+9)x2+13x+6a is reciprocal of other then find the value of a????

Answer 1

HEY MATE!

HERE IS YOUR ANSWER:

STEP BY STEP EXPLANATION:

Let one zero be x so, other zero will be 1/x

Now , in (a^2+9)x^2+13x+6a=0 ; a=(a^2+9), b=13 and c=6a

We know that product of zeroes = c/a

so, x×1/x=6a/a^2+9

1=6a/a^2+9

a^2+9=6a

a^2-6a+9=0

a^2-3a-3a+9=0

a(a-3)-3(a-3)=0

(a-3)(a-3)=0

So, value of a=3

Hope it helped^_^