If one zero of the polynomial ax*2+15x+6 is reciprocal of the other then find the value of a also find the zeros of the polynomial
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Let's assume that the two zeros be α and (1/α)
Now In case of polynomial ax²+bx+c=0
product of zeros = (c/a)
so in polynomial ax²+15x+6=0
productof zeros = α(1/α) = (6/a)
1=(6/a)
a=6
Now In case of polynomial ax²+bx+c=0
product of zeros = (c/a)
so in polynomial ax²+15x+6=0
productof zeros = α(1/α) = (6/a)
1=(6/a)
a=6
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