Question

If one zero of the polynomial ax^2+bx+c is double the other prove that 2b^2=9ac

Answer 1

Answer:

2b^2=9ac

Step-by-step explanation:

let one zero of polynomial ax^2+bx+c be a

the other zero is double hence 2a

sum of roots of quadrati:

=> a+2a=-b/a

=> 3a= -b/a

=> a= -b/a ...... (I)

product of roots of quadratic

= a×2a: c/a

= 2a^2 = c/a

substituting value of a from (I)