If one zero of the polynomial Kx^2+4x+8-k is reciprocal of the other then find the value of K
Answers
Answered by
10
Hi Friend,
Let the one zero of the given polynomial be Alpha
Then,
The other zero is 1/Alpha
Therefore,
Product of zero = (Alpha × 1/Alpha) = 1
But,
Product of zeros = Constant term/Coefficient of X² = 8-K/K
Therefore,
8-K/K = 1
8-K = K
2K = 8
K = 8/2
K = 4
Hence,
K = 4
HOPE IT WILL HELP YOU..... :-)
Let the one zero of the given polynomial be Alpha
Then,
The other zero is 1/Alpha
Therefore,
Product of zero = (Alpha × 1/Alpha) = 1
But,
Product of zeros = Constant term/Coefficient of X² = 8-K/K
Therefore,
8-K/K = 1
8-K = K
2K = 8
K = 8/2
K = 4
Hence,
K = 4
HOPE IT WILL HELP YOU..... :-)
Answered by
0
Step-by-step explanation:
Hi friends,
Let the one zero of the given polynomial be alpha
then,
the other zero is the 1/alpha
therefore,
product of zeros =constant term/coefficient of x^2=8-k/k
therefore,
8-k/k=1
8-k=k
2k=8
k=8/2
k=4
so, the answer is
k=4
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