if the HCF of65 and 117 is expressible in the form of 65m- 117 then find the valu of m
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5
the hcf of 65 and 117 is
65=5×13
117=3×3×13
hence hcf is 13
now expressed it in a given equation
65m-117=13
65m=13+117
65m=130
m=2 ans
65=5×13
117=3×3×13
hence hcf is 13
now expressed it in a given equation
65m-117=13
65m=13+117
65m=130
m=2 ans
Answered by
0
hcf of 65 and 117 is 13
13 = 65m+117
m=1.6
13 = 65m+117
m=1.6
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