Question

if one zero of the polynomial kx2+10x+k is -1/3, then value of k is . options a) 3 b) 9 c) 10. d) -3​

Answer 1

Answer:

hope it will help you:-)

Answer 2

Answer:

p(x) = kx²+10x+k

p(-1/3) = k×(-1/3)²+10×(-1/3)+k

0= k×1/9-10/3+k

0= k/9-10/3+k

0= k-30+9k/9

0= 10k-30/9

0×9= 10k-30

0 = 10k-30

0+30= 10k

30= 10k

30÷10= k

3= k

(a) 3

This option is right.