If one zero of the polynomial p(x) = ax - 3
(a-1) x-1 is 1, then value of a is :
(a) 1 (B)1 (c) 2 (d) - 2
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Answer:
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Step-by-step explanation:
p(x)=ax - 3 (a-1) x-1
p(1)=a(1) - 3 (a-1) (1)-1
0=a - 3 (a-1)-1
0=a-3a+3-1
0=-2a+2
-2=-2a
a=-2/-2
a=1
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