Math, asked by nickunj, 10 months ago

If one zero of the polynomial p(x) = ax - 3
(a-1) x-1 is 1, then value of a is :
(a) 1 (B)1 (c) 2 (d) - 2​

Answers

Answered by manyaarora2311205
2

Answer:

1

Step-by-step explanation:

p(x)=ax - 3 (a-1) x-1

p(1)=a(1) - 3 (a-1) (1)-1

0=a - 3 (a-1)-1

0=a-3a+3-1

0=-2a+2

-2=-2a

a=-2/-2

a=1

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