Question

if one zero of the polynomial p(x)=x^-x-(2+2k) is -4 then find the value of k.

Answer 1

x square - x - (2+2k)

one of the zero is -4

since -4 is one of the zero of this equation then putting value of x = -4 will give equation = 0

solution —

x square - x - (2+2k)

putting x = -4

(-4)square - (-4) - (2+2k) = 0
8 + 4 - 2 - 2k = 0
10 - 2k = 0
-2k = -10
k = 5