Question

if one zero of the polynomial q(x) =x²+px+8 is double the other,then find the value of p and hence both zeros of q(x)​

Answer 1

Answer:

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Step-by-step explanation:

p(x)=x²+px+8..

take 1 zero as alpha

and the other as 2×alpha as it is twice the first zero...

hope it helps...

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Answer 2

Answer:

let the one zero be A

then 2nd= 2A

product of zeroes

= A×2A = constant term/coef of x^2

2A^2=8/1

A^2=4

A=√4

A=2

sum of zeroes

2A+A = -ceoff of x/coeff of x^2

3A = -p/1

3×2=-p

6=-p

p=-6

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