if one zero of the polynomial x square minus 8 x + k exceeds other by 2 find the value of k
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the value of k is 211
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Answer:
k = 15
Here is the Step-by-step explanation:
so given : we have two zeroes and one of them exceeds the other by two
let us take the two zeroes as : α = n and β = 2+n
also, p(x) = x^2 - 8x + k
Solution : by using our formulas
α + β = - b / a
n + 2 + n = -(-8) / 1 = 8
thus, 2n + 2 = 8
2n = 6
n = 3 .. (i)
now using the 2nd formula,
α * β = c/a
n(n+2) = k/1
n^2 + 2n = k
substituting the value of n from i
3^2 + 2(3) = k
9 + 6 = k
15 = k
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hope you find this helpful :)
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